Question

If the sum of two consecutive ever
numbers is 66, then the smaller one is
(A) 34
( (B) 32
(C) 42
(D) 24​

Answer 1

Answer:

32 and 34

Step-by-step explanation:

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Answer 2

Answer:

both option A and B

Step-by-step explanation:

Two integers summing to 66 can be represented by the equation:

x + y = 66.

X and Y are two consecutive even integers meaning they are divisible by two and right next to each other in the list of even integers. Therefore the larger integer in the list will be two more than the lesser integer in the list.

y = x + 2.

Plugging into the first equation yields:

x + x + 2 = 66

-> 2x + 2 = 66

->2(x + 1) = 66 [distributive property]

->x + 1 = 33 [divide both sides of equation by 2]

-> x = 32 [subtract both sides by 1]

Thus, the two consecutive even integers that add to 66 are 32 and 34.

Check: 32 + 34 = 66. 32/2 = 16. 34/2 = 17. 32 and 34 are both even and consecutive.