Question

If the sum of two digit number and the number obtained by reversing the digit is 55 find the sum of the the digits of the two digit number.​

Answer 1

Answer:-

The sum of the digits of the two digit number (x + y) is 5.

Solution:-

Let:-

The digit in the tenth place be y.

The digit in the one's place be x.

Then:-

Original number is 10y + x.

According to Question:-

On reversing the digit the number is 10x + y.

Now:-

We can solve the equation easily

=> 10y + x + 10x + y = 55

=> 11y + 11x = 55...........(i)

Now divide the equation (i) by 11

=> 11y + 11x = 55

=> 11y/11 + 11x/11 = 55/11

=> y + x = 5

Therefore:-

The sum of the digits of the two digit number (x + y) is 5.

Answer 2

Answer:

x + y = 5

Step-by-step explanation:

Assume that the ten's digit number be x and one's digit number be y.

Therefore, the number is 10x + y.

Given that, the sum of two digit number and the number obtained by reversing the digit is 55.

We have to find the sum of the the digits of the two digit number.

As original number is 10x + y. So, the reversed number is 10y + x.

As per given condition,

→ 10x + y + 10y + x = 55

→ 11x + 11y = 55

Take 11 as common

→ 11(x + y) = 11(5)

11 throughout cancel

→ x + y = 5

Hence, the sum of the the digits of the two digit number is 5.