Question

. If the sum of two-digit numbers and

the number formed after interchanging the

digits is 110, then find the number, if the

difference of their digits is 4


please solve this question ​

Answer 1

Mark this as the BRAINLEST ANSWER

48 is the answer

Step-by-step explanation:

let the two digit no. be 10x + y

and the no. when reversed be 10y + x

according to the question :

10x + y + 10y + x = 132

11x + 11y = 132

taking 11 common

11(x + y ) = 132

x + y = 12 ----------- 1)

lets do the second part

Now,

10x + y + 12 = 5(x + y)

10x + y + 12 = 5x + 5y

5x + 12 = 4y

4y - 5x = 12 ------ 2)

substituting y = 12 - x in equation 2)

4( 12 - x ) - 5x = 12

48 - 4x - 5x = 12

48 - 12 = 9x

36 = 9x

x = 4

x + y = 12

4 + y = 12

y = 8

so the no. is 48

Hope it will help you

Answer 2

x + y = 4

xy+yx=110

7-3 =4

73+37=110

Answer = 73