If the sum of two digits number and number obtained by reversing the digits is 44, find the sum of the digits of the 2 digits number
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Let the two digit numbers be 10x+y.
Therefore the number obtained by reversing the digits is 10y+x.
So,
10x+y + 10y+x = 44
11x + 11y = 44
11 (x + y) = 11 × 4
x + y = 4 [Dividing both sides by 11]
So here, the sum of the digits of the numbers us 4
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Answer
Original Number = 10x + y
Reversed number = 10y + x
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