Question

if the sum of two digits of a two digit number is 9,if the digits are reversed the ration is 3:8 to orginal number..

Answer 1

Let the required number be 10x+y.

Given :

x+y=9 -> eq1

Also 10x + y / 10y + x = 3/8

=> 80x + 8y = 30y+3x

77x =22y

=> 77x =22(9-x) By eq1

77x =198-22x

99x=198

|x=2|

From eq1, y =7

Thus required number =10(2) +7

=27

Answer 2

For solution refer to the attachment :)