Question

If the sum of two fractions is 7/8, then one of the fraction is 1/4, then how much of the other fraction will be?

Answer 1

$\Large{\underline{\underline{\bf{Given:-}}}}$

$sum \: of \: two \: fraction \: is = \frac{7}{8} \\ \\ one \: of \: the \: fraction \: is = \frac{1}{4}$

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$\Large{\underline{\underline{\bf{To\: find:-}}}}$

Other fraction = ?

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$\Large{\underline{\underline{\bf{Solution:;}}}}$

Let the other fraction be x

${\bold{\underline{\underline{According\: to \: the \: Question:-}}}}$

$⟹\frac{1}{4} + x = \frac{7}{8} \\ \\ ⟹ x = \frac{7}{8} - \frac{1}{4} \\ \\⟹ x = \frac{7 - 2}{8} \\ \\ ⟹x = \frac{5}{8}$

$\boxed{x=5/8}$

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$\Large{\underline{\underline{\bf{Verification:-}}}}$

$⟹\frac{1}{4} + \frac{5}{8} = \frac{7}{8} \\ \\ ⟹\frac{2 + 5}{8} = \frac{7}{8} \\ \\ ⟹\frac{7}{8} = \frac{7}{8}$

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$\Large{\underline{\underline{\bf{Hence\: Verified!}}}}$

Answer 2

Given:-

Sum of two fractions = 7/8

one fraction= 1/4

To find:-

Other fraction

Solution:-

Let the one other fraction be x

According to the question:-

$\frac{1}{4} + x = \frac{7}{8} \\ \\ \frac{1}{4} - \frac{7}{8} = x \\ \\ \frac{2 - 7}{8} = x \\ \\ \frac{ - 5}{8} = -x$

$\boxed{x=5/8}$

Hope it helps uh !