Question

if the sum of two natural numbers is 28 and their product is 192 find the numbers

Answer 1

let first no = x
second no = y

x + y = 28
x= 28 - y -------------(1)




poduct of number = x * y = 192---------(2)

putting value of x in 2nd
(28-y)*y =192
28y - y2 =192
28y -y2-192= 0
y2-28y+192=0
y2-(16+12)y+192=0
y2-16y-12y+192=0
y(y-16)-12(y-16)=0
(y-16)(y-12)
y-16=0
y=16,12

Answer 2

Step-by-step explanation:

For solution please check the attachment

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