Question

if the sum of two number is 1215 and their HCF is 81 . find the number of such pairs

Answer 1

Answer:

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Answer 2

Given:

The two number is 1215 and HCF is 81.

To Find:

Find the number of such pairs.

Step-by-step explanation:

The two numbers be $x$ and $y$

$81x+81y=1215$

$81(x+y)=1215$

$x+y=15$

$x=1,y=14$ the numbers are,

$1*81+14*81=81+1134$

$=1215$

$x=7,y=8$ the numbers are,

$7*81+8*81=567+648$

$=1215$

$x=2,y=13$the numbers are,

$2*81+13*81=162+1053$

$=1215$

$x=4,y=11$the numbers are,

$4*81+11*81=324+891$

$=1215$

Answer:

Therefore, The numbers of such pairs are$4$.