Question

if the sum of two number is 184 one third of a first number exercised on seventh of another number by 8 find the number​

Answer 1

Answer:

72, 112

Step-by-step explanation:

x + y = 184 --(1)

x/3 - y/ 7 = 8

7x - 3y = 168 --(2)

multiply 1 by 3 & 2 by 1 , we get

3x + 3y = 552

7x - 3y = 168

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10x = 720 => x = 72 & from (1)

y = 184 - 72 = 112