If the sum of two number is 20 and
their cube is 2240. Find the sum of their
square
A. 206
B. 208
C. 210
D. 212
Answers
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1
Answer:
Let the two numbers be x and y.
According to the given condition
》x + y = 20 ... (1)
》x³ + y³ = 2240 ... (2)
a³ + b³ = (a + b)³ - 3ab (a + b)
We get
》2240 = 8000 - 3 ab (20)
》60 ab = 5760
》ab = 96
Now,
》x³ + y³ = (x + y) (x² + y² - xy)
》2240 = 20 (x² + y² - 96)
》x² + y² - 96 = 112
》x² + y² = 208
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