if the sum of two number is 63 and their difference is 13.then what is the product of those number.?
Answers
let the two numbers be x and the other is y
x+y=63......(1)
x-y= 13......(2)
2x= 76
x=38
x+y=63 ( from 1)
38+y=63
y=63-38
y=25
the product of those number =xy =38x 25 = 950
the product of those number is 950.
Given :–
- Sum of two numbers = 63.
- Difference of two numbers = 13.
To Find :–
- Product of those numbers.
Solution :–
Let,
The first number be x.
And the second number be y.
So,
According to the question,
- x + y = 63 –––––––(1)
- x – y = 13 –––––––(2)
First, we have to find the value of y.
So,
From equation (2),
⟹ x – y = 13
- x = 13 + y
Substitute this value in equation (1),
- x + y = 63
⟹ 13 + y + y = 63
⟹ 13 + 2y = 63
⟹ 2y = 63 – 13
⟹ 2y = 50
⟹ y =
Cut the denominator and the numerator by 2, we obtain
⟹ y = 25
- y = 25
Now, put the value of y in equation (2),
- x – y = 13
⟹ x – 25 = 13
⟹ x = 13 + 25
⟹ x = 38
Hence,
- First number is 38.
- Second number is 25.
Check :–
1. Sum of two numbers is 63.
⟹ x + y = 63
- x = 38
- y = 25
⟹ 38 + 25 = 63
⟹ 63 = 63
2. Difference of two numbers is 13.
⟹ x – y = 13
- x = 38
- y = 25
⟹ 38 – 25 = 13
⟹ 13 = 13
In both 1 and 2 checking the L.H.S. and the R.H.S. is equal.
So, the answer is correct.
Now, we need to find the products of both numbers.
So,
⟹ x × y
- x = 38
- y = 25
⟹ 38 × 25
⟹ 950
Hence,
The product of those numbers is 950.