Question

if the sum of two number is divided by 12 quotient is obtained is 3 and remainder is 4 if the difference of the same number is divided by 4 then quotient is 1 and remainder is 2 find the number​

Answer 1

Step-by-step explanation:

let the two numbers be x and y

using

dividend = divisor * quotient + remainder

1st condition

x+y =12*3+4

x+y=40........(1)

2nd condition

x-y=4*1+2

x-y=6..…......(2)

add(1)and(2)

x+y+x-y=40+6

2x=46

x=46/2

x=23

put x=23 in (2)

23-y=6

-y=6-23

-y=-17

y=17

the two numbers are 23 and 17

Answer 2

Answer:

23 and 17

Step-by-step explanation:

Let the two numbers be x and y

According to first condition,

Dividend = Divisor × Quotient + Remainder

x + y = 12 × 3 + 4

• x + y = 40

According to second condition,

Dividend = Divisor × Quotient + Remainder

x - y = 4 × 1 + 2

• x - y = 6

Adding equations 1 and 2

x + y = 40

x - y = 6

2x = 46

x = 46

2

• x = 23

Substituting x = 17 in equation 1

x + y = 40

23 + y = 40

y = 40 - 23

• y = 17

Therefore, the two numbers are 23 and 17;

where x = 23 and y = 17.