if the sum of two numbers be multiplied by each number separately, the products so obtained are 247 and 114. The sum of the number is.
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Let the numbers be 'a' & 'b'
(a+b)*a = 247
(a+b)*b = 114
a^2 + ab = 247
b^2 + ab = 114
Subtract above 2
a^2 - b^2 = 133
(a+b)*(a-b) = 133
(a+b)*(a-b) = 19 * 7
a= 13, b =6
[a+b = 19, a-b = 7...adding: 2a = 26, a=13..hence b = 6]
Hence numbers are 13,6
And sum of numbers is: 13+6 = 19
Hope it helps.
(a+b)*a = 247
(a+b)*b = 114
a^2 + ab = 247
b^2 + ab = 114
Subtract above 2
a^2 - b^2 = 133
(a+b)*(a-b) = 133
(a+b)*(a-b) = 19 * 7
a= 13, b =6
[a+b = 19, a-b = 7...adding: 2a = 26, a=13..hence b = 6]
Hence numbers are 13,6
And sum of numbers is: 13+6 = 19
Hope it helps.
Answered by
3
Answer: 19
Step-by-step explanation:
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