Question

If the sum of two numbers is 08 and their differences is 4 times the sum find the numbers (substitution method)

Answer 1

HEY!!!!!!!

let the numbers be x and y
x + y = 8 ....(1).........---> X = 8 - y

HERE ARISES 2 CASES
WHETHER,
CASE:(1):-----X > Y
X - Y = 4(8)= 32......(2)

CASE :2 Y > Xy
Y - X = 32........(3)

NUMBERS ARE:---
PUT VALUE OF X IN (2)
8 - y - y = 32 => -2y =24

y =-12
x =20

PUT IN (3)VALUE OF X

Y -(8-Y) =32
y -8 +y =32
2y =40

y=20
x =-12

REGARDS ✌

Answer 2

Hey friend

Let the two no. be X and Y

So, the equation according to the question will be

=>X+Y=8. eq.1
X-Y=4. eq.2

Taking Eq.1

X+Y=8
X=8-Y

Substitute X=8-Y in eq.2

=>8-Y-Y=4
=>8-2Y=4
=>4=2Y
=>Y=2

Substituting Y=2 in eq.1

=>X+2=8
=>X=6

So, the numbers are 6 and 2


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