Question

if the sum of two numbers is 11 and sum of their cubes is 737, find the sum of their squares

Answer 1

x+y=11

(x^³+y^³)=737

(x+y)³=x³+y³+3xy(x+y)

11³=737+3xy(11)

1331-737=33xy

594÷33=xy

18=xy

(x+y)²=x²+y²+2xy

121=x²+y²+36

x²+y²=85