if the sum of two numbers is 11 and sum of their cubes is 737, find the sum of their squares
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x+y=11
(x^³+y^³)=737
(x+y)³=x³+y³+3xy(x+y)
11³=737+3xy(11)
1331-737=33xy
594÷33=xy
18=xy
(x+y)²=x²+y²+2xy
121=x²+y²+36
x²+y²=85
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