Question

if the sum of two numbers is 1215 and hcf is 81 find such pairs of number

Answer 1

so acc to me the answer will be 81×8=> 648
81×7=> 567... hope it helps

Answer 2

It is given that the sum of two numbers is 1215 and their H.C.F is 81

Since the H.C.F of two numbers is 81, the two numbers are 81x and 81y.

Now, 81x + 81y = 1215 [Sum of two numbers is 1215]

81 (x + y) = 1215

(x + y) = 15

So,

For x = 7, y = 8; in this case the numbers are 7 × 81 = 567 and 8 × 81 = 648

x = 1, y = 14; in this case the numbers are 1 × 81 = 81 and 14 × 81 = 1134

x = 2, y = 13; in this case the numbers are 2 × 81 = 162 and 13 × 81 = 1053

x = 4, y = 11; in this case the numbers are 4 × 81 = 324 and 11 × 81 = 891

So the number of such pairs are 4