Question

If the sum of two numbers is 14 and multiplication is 40,then find their difference.

Answer 1

Given:-

•Sum of two numbers is 14 and multiplication is 40.

To Find:-

•Find their difference.

Solution:-

Let consider the numbers are x and y.

According to the question,

x+y = 14,

xy = 40

we know that

$\: \: \sf \: {(x - y)}^{2} = {(x + y)}^{2} - 4xy$

Now put on the values

$\: \: \sf \: {(x - y)}^{2} = {(14)}^{2} - 4 \times 40 \\ \\ \: \: \sf {(x - y)}^{2} = 196 - 160 \\ \\ \: \: \sf \: {(x - y)}^{2} = 36 \\ \\ \: \: \sf \: x - y = \sqrt{36} = 6$

Hence,difference number is 6.