if the sum of two numbers is 15 and their hcf is 5 . find all such possible pair of numbers
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The sum of two numbers is 84 and their HCF is 12. How many such pairs are there?
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As both the numbers have the highest common factor 12 it clearly means that the both the numbers are the multiples if 12
So let the numbers be 12x and 12y
As given their sum is 84
ATQ,12x+12y=84
12 (x+y)=84
x+y=7
So the number of pairs with 7 as their sum are (1,6),(2,5),(3,4)
That is three pairs
So the numbers are (12,72),(24,60), (36,48)
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