Question

If the sum of two numbers is 15 and their HCF is 5. Find all such possible pairs of numbersb
answer:
let the numbers be x and y
--- x + y = 15
--- HCF of x and y = 5
if we take HCF of x and y we get 1 but HCF here is 5
so,
5x+5y=15
5(x+y) = 15
x+y = 15/5
x+y = 3
so, the possible pair is (1,2)
x=1 and y=2
----- 5(1) + 5(2) = 15
5+10=15.
HCF of 5,10 is 5.
so the possible pair is (5,10) where the sum is 15 and their HCF is 5​

Answer 1

Step-by-step explanation:

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