if the sum of two numbers is 18 and sum their square is164 then the smallest number is
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Let the two numbers be x and y.
According to given condition,
x + y = 18
=> x = 18 - y ...(i)
x² + y² = 164...(ii)
Substitute (i) in eqⁿ (ii)
x² + y² = 164
⇒ (18 - y)² + y² = 164
⇒ 324 + y² - 36y + y² = 164
⇒ 2y² - 36y + 324 - 164 = 0
⇒ 2y² - 36y + 160 = 0
⇒ 2 (y² - 18y + 80) = 0
⇒ y² - 18y + 80 = 0
⇒ y² - 10y - 8y + 80 = 0
⇒ y ( y - 10 ) - 8 ( y - 10 ) = 0
⇒ ( y - 10 ) ( y - 8 ) = 0
⇒ y = 10 or y = 8
Therefore, numbers are 10 and 8.
Smallest number = 8
sonalinRath:
thnx
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