Question

If the sum of two numbers is 184 and 1/3 of one number exceeds 1/7 of the other number by 8 what are the two numbers

Answer 1

Step-by-step explanation:

Answer:

Smaller number = 72

Step-by-step explanation:

Let the first number be x

Let the second number be y

We are given that the sum of two numbers is 184

So,x+y=184x+y=184 --1

Now we are given that one-third of the one exceeds one - seventh of the other by 8

So, A.T.Q

\frac{x}{3}-\frac{y}{7}=8

3

x

−

7

y

=8

\frac{7x-3y}{21}=8

21

7x−3y

=8

7x-3y=8 \times 217x−3y=8×21

7x-3y=1687x−3y=168 --2

Now substitute the value of x from 1 in 2

7(184-y)-3y=1687(184−y)−3y=168

1288-7y-3y=1681288−7y−3y=168

1288-168=10y1288−168=10y

1120=10y1120=10y

So, y =112

Substitute the value of y in 1

x+112=184x+112=184

x=184-112x=184−112

x=72x=72

Hence the smaller number is 72.