If the sum of two numbers is 20 and the difference is 8 then what are the two numbers
Answers
Answer:
Sum: 14 + 6 = 20
Difference: 14 - 6 = 8
Step-by-step explanation:
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Let's start by calling the two numbers we are looking for x and y.
The sum of x and y is 20. In other words, x plus y equals 20 and can be written as equation A:
x + y = 20
The difference between x and y is 8. In other words, x minus y equals 8 and can be written as equation B:
x - y = 8
Now solve equation B for x to get the revised equation B:
x - y = 8
x = 8 + y
Then substitute x in equation A from the revised equation B and then solve for y:
x + y = 20
8 + y + y = 20
8 + 2y = 20
2y = 12
y = 6
Now we know y is 6. Which means that we can substitute y for 6 in equation A and solve for x:
x + y = 20
x + 6 = 20
X = 14
Summary: The sum of two numbers is 20 and their difference is 8. What are the two numbers? Answer: 14 and 6 as proven here:
Sum: 14 + 6 = 20
Difference: 14 - 6 = 8
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Let the two numbers be "x" and "y".
It is given that the sum of two numbers is 20.
Therefore,
x + y = 20
On simplifying the above equation; we get:
x = 20 - y (Equation 1)
It is given that the difference of two numbers is 8.
x - y = 8
On putting the value of "x" from Equation 1 ; we get:
x - y = 8
=> x = 8 + y
=> 20 - y = 8 + y
=> 20 - 8 = y + y
=> 12 = 2y
OR
=> 2y = 12
=> y = 12/2
=> y = 6
Putting the value of y in Equation 1
x = 20 - y
x = 20 - 6
x = 14
Therefore,
The numbers are 6 and 14.
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