If the sum of two numbers is 24 and their products is 108 then find the sum of their reciprocal?
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Step-by-step explanation:
let the nos. be x and 24-x
given that : (x)(24-x)= 108
24x - x² = 108
x² - 24x + 108 = 0
x² - (18 + 6)x + 108 = 0
x² - 18x - 6x + 108 = 0
x(x - 18) - 6(x - 18) = 0
(x - 18) (x - 6) = 0
x = 18 or x = 6
if x = 18 then the no. will be 24
if x = 6 then the no. will be 24
sum of reciprocal will be 4 + 2 = 6
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