If the sum of two numbers is 4 and their product is 3, then what is the sum of their squares?
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Let the numbers are a and b.
According to the question:
⇒ ab = 3
⇒ a + b = 4
Square on both sides :
⇒ ( a + b )^2 = 4^2
⇒ a^2 + b^2 + 2ab = 4^2
⇒ a^2 + b^2 = 16 - 2ab
⇒ a^2 + b^2 = 16 - 2( 3 ) { ab = 3 }
⇒ sum of squares = 16 - 6
= 10
Cube on both sides:
⇒ ( a + b )^3 = 4^3
⇒ a^3 + b^3 + 3ab( a + b ) = 64
⇒ a^3 + b^3 + 3( 3 )( 4 ) = 64
⇒ a^3 + b^3 = 64 - 3( 3 )( 4 )
⇒ a^3 + b^3 = 64 - 36
⇒ sum of cubes = 28
HOPE IT HELP YOU!!!!!
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