If the sum of two numbers is 48 and their gcd and lcm are 2 and 286 then what is the sum of the inverse of those numbers?
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Step-by-step explanation:
let the ratio of the no. be x : y
then the no. be (gcd ×ratio)
no. be 2x and 2y
sum of the no. = 48
2x+2y= 48
x+y= 48/2=24
LCM of the no. = 286
2×x×y= 286
xy= 143
(x-y)²= (x+y)²-4xy
(x-y)² = (24)²-4×143
(x-y)²= 576- 572
(x-y)²= 4
x-y= 2
x+y= 24
on adding both eq
2x= 26
on subtracting both eq.
2y= 22
the no is 2x and 2y
hence no. be 26 and 22
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