Question

If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to

A) 55/601 B) 601/55 C) 11/120 D) 120/11

Answer 1

Answer:

product of numebrs = 5 x 120 = 600 factors = 5 x 5 x 3 x 2 x 2 x 2

sum is = 55

xy = 600

x + y = 55

reciprocal

1/x + 1/y = (x+y)/xy = 55/600 = 11/120