Question

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to ?
A) 13/125
B) 14/57
C) 11/120
D) 16/41

Answer 1

Answer: Option C

Explanation:

Let the numbers be a and b.

Then, a + b = 55 and ab = 5 x 120 = 600.

The required sum =1+1=a + b=55=11abab600120

Answer 2

Hey mate ^_^

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Answer:
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Let the numbers be 'x' and 'y'.

We know that,

Product of two numbers = Product of their HCF and LCM

Then,

$a + b = 55$

And,

$ab= 5 × 120 = 600$

The required sum,

$= ( \frac{1}{a} ) + ( \frac{1}{b} )$

$= \frac{(a + b)}{ab}$

$= \frac{55}{600}$

$= \frac{11}{120}$

Therefore,

Correct option C) $\frac{11}{120}$

#Be Brainly❤️