IF THE SUM OF TWO NUMBERS IS 55 AND THE HCF AND LCM OF THESE NUMBERS ARE 5 &120 RESPECTIVELY THEN THE SUM OF THE RECIPROCALS OF THE NUMBERS IS EQUAL TO ?
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Answered by
0
Answer:
5/24
Step-by-step explanation:
i thin that if the number is 5 and 120 the their reciprocal should be 1/5 and 1/120
1/5+1/120=24+1/120=25/120=5/24
sonalinRath:
ans 11 /120 but How ? please help me
Then, a + b = 55 and ab = 5 x 120 = 600.
The required sum =1/a+1/b = a+b/ab= 55/600=11/20
Answered by
8
Let the numbers be x and y.
Now according to the question,
x + y = 55
HCF(x,y)=5 and LCM(x,y)= 120
We, know that xy=HCF(x,y) × LCM(x,y)
So, xy=120×5
Now, Sum of their resiprocal:
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Here is your answer
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Now according to the question,
x + y = 55
HCF(x,y)=5 and LCM(x,y)= 120
We, know that xy=HCF(x,y) × LCM(x,y)
So, xy=120×5
Now, Sum of their resiprocal:
☝☝☝☝☝☝☝☝☝
Here is your answer
✒✒✒✒✒✒✒✒✒✒✒✒✒✒✒✒✒✒✒✒✒
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