Question

if the sum of two numbers is divided by 15 ,the quotient is 2 and the remainder is 10 if the difference of the same no is divided by 3 , then the quotient is 4 and the remainder is 2 find the numbers

Answer 1

Let the 2 numbers be a and b
Given :
a + b = 15(2) +10
a - b = 3(4) +2

So
a + b = 40____(1)
a - b = 14____(2)
By (1) and (2)
a + b -26 = a -b
- 2b = -26
b = 13
So by (1) or (2)
a = 27

Answer 2

The numbers are 27 and 13

Step-by-step explanation:

Let the numbers be x and y

Sum of numbers = x+y

We are given that the sum of two numbers is divided by 15 ,the quotient is 2 and the remainder is 10

Dividend = x+y

Divisor = 15

Quotient = 2

Remainder = 10

$Dividend = (Divisor \times Quotient)+Remainder$

$x+y = (15 \times 2)+10$

$x+y = 40$ -- A

Difference of two numbers = x-y

We are given that the difference of the same no is divided by 3 , then the quotient is 4 and the remainder is 2

Dividend = x-y

Divisor = 3

Quotient = 4

Remainder = 2

$Dividend = (Divisor \times Quotient)+Remainder$

$x-y = (3 \times 4)+2$

$x-y =14$ --B

Add A and B

$x+y+x-y = 40+14$

$2x = 54$

$x = 27$

Substitute the value of x in A

$27+y = 40$

$y=40-27$

$y=13$

Hence the numbers are 27 and 13

#Learn more :

If the sum of two numbers is divided by 13, the quotient is 4 and the remainder is 8. If difference of the same two numbers is divide by 4, the quotient is 3 and the remainder 2. Find the numbers

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