Question

If the sum of two positive integers is 36 greater than their different find the smallest among them

Answer 1

Answer:

Smaller number is 18

Step-by-step explanation:

Let the two numbers be p and q with  (p>q)

Sum of numbers = $p+q$

Difference of numbers = $p-q$

According to given question,

$p+q=p-q+36$ .......(1)

$q=36-q$

$q+q=36$

$2q=36$

$q=\frac{36}{2}$

$q=18$

Thus,  Smaller number is 18 as (p>q).