Question

If the sum of two positive integers is 36 greater than their difference,find the smallest among those positive integers.

Answer 1

Answer:

Smaller no is 18.

Step-by-step explanation:

➡️ Let one positive integer be x and other be y. (x> y)

Then,

Sum of nos = x + y

Difference of nos = x - y

According to question :

➡️ x + y = x - y + 36

➡️ y = - y + 36

➡️ y + y = 36

➡️ 2y = 36

➡️ y = 18.

Hence smaller no is 18.

Answer 2

18. the smaller one here is your and