If the sum of two positive integers is 36 greater than their difference,find the smallest among those positive integers.
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Answered by
1
Answer:
Smaller no is 18.
Step-by-step explanation:
➡️ Let one positive integer be x and other be y. (x> y)
Then,
Sum of nos = x + y
Difference of nos = x - y
According to question :
➡️ x + y = x - y + 36
➡️ y = - y + 36
➡️ y + y = 36
➡️ 2y = 36
➡️ y = 18.
Hence smaller no is 18.
Answered by
0
18. the smaller one here is your and
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