Question

if the sum of w consecutive number is 93 and one of them is x and other is 3 more than half of x find the numbers
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Answer 1

Answer:

Well first is that we need to express the problem into a mathematical equation.

Since it is consecutive we’ll be assigning polynomial expressions to each number.

Say…

First number: x

Second number: x + 1

Third number: x + 2

Next is writing the equation..

That would be

○ (First number) + (second number) + (third number) = 93

○ (x) + (x + 1) + (x + 2) = 93

Next is simplifying the equation by adding like terms. Since the variables are just the same, we’ll be adding them like what we’ll be doing with just plain numbers and that would be…

○ 3x + 3 = 93

Then do the math by finding out what x is by isolating it to one side and letting it end up as a simple x. No coefficients except for 1.

○ 3x = 93 -3

○ 3x = 90

○ 3x/3 = 90/3

○ x = 30

After finding x, let’s substitute it to find the value of the numbers…

Remember that…

First number: x

Second number: x + 1

Third number: x + 2

So..

1st no. : x = 30

2nd no. : x + 1 = 30 + 1 = 31

3rd no.: x + 2 = 30 + 2 = 32

To check:

1st no. + 2nd no. + 3rd no. = 93

30 + 31 + 32 = 93

93 = 93

The three numbers are : 30, 31, and 32

Step-by-step explanation:

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