If the sum of x and its reciprocal is 26/5 then x is
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LET NUMBER BE X
A/Q
X+ 1/X=26/5
X^2 +1/X=26/5
26X=5X^2+5
5X^2 -26X+5=0
5X^2 -25X -X+5=0
5X(X-5) -1(X-5)=0
(5X-1)(X-5)
THERE ARE TWO RESULTS
5X-1=0
5X=1
X=1/5
OR
X-5=0
X=5
MARK ME AS BRAINLIEST
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