If the sum of zero of polynomial p (x)=(k square-14)x square-2x-4 is 1.then find value of k
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p(x)=(k^2-14)x^2-2x-4
sum of roots =1=-b/a
so ; here, b=-2 and a=k^2-14
so according to the question:-
-(-2)/(k^2-14)=1
2/(k^2-14)=1
2=k^2-14
16=k^2
therefore k=4 (√16=4)
thank u,hope it helps!^_^
sum of roots =1=-b/a
so ; here, b=-2 and a=k^2-14
so according to the question:-
-(-2)/(k^2-14)=1
2/(k^2-14)=1
2=k^2-14
16=k^2
therefore k=4 (√16=4)
thank u,hope it helps!^_^
sujaljuneja229:
Is it right?
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