Question

if the sum of zeroes of a quadratic polynomial KY'2+2y-3k is twice their product then find the value of k

Answer 1

Heya !!!



P(X) = KY²+2Y - 3K



Here,


A = K , B = 2 and C = -3K



Sum of zeroes = -B/A


Alpha + Beta = -2/K --------(1)


and,


Product of zeroes = C/A



Alpha × Beta = -3K/K = -3



According to question,



Sum of zeroes = 2 × (Product of zeroes)


-2/K = 2 × (-3)



-2/K = -6


-6K = -2



K = -2/-6 = 1/3




HOPE IT WILL HELP YOU....... :-)