Question

If the sum of zeroes of quadratic polynomial 3xsquare-kx+6 is 3 , then find the value of k​

Answer 1

GIVEN :

Quadratic Polynomial = 3x² - Kx + 6

Sum of Zeroes of Quadratic Polynomial = 3

Let the zeroes be α and β

α + β = 3

We know that,

Using Co - effecients : α + β = -b/a

-(-k)/3 = 3

k/3 = 3

k = 3 × 3

k = 9

Therefore, the value of k is 9.

Answer 2

$\mathbf{\huge{\boxed{\underline{\red{k = 9}}}}}$

$\rule{200}{2}$

$\mathfrak{\large{\underline{\underline{\blue{Explanation}}}}}$

Quadratic polynomial =

3x² - kx + 6

a = 3

b = -k

c = 6

$\rule{200}{2}$

Let zeroes be α and β

Their sum is given 3

So,

α+β=3

We know, that α+β=-b/a

put values of a and b

We, have

-(-k) /3 = 3

k /3=3

k=9

--------[ Answer ]

$\rule{200}{2}$

So, value of k is 9

$\rule{200}{2}$

Hope it helps

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