Question

If the sum of zeroes of the polynomial f(x) 2x³-3kx²+4x-5 is 6, then find value of k

Answer 1

Given,

A polynomial f(x) = 2x³-3kx²+4x-5

The sum of zeroes of this polynomial is 6.

To Find,

The value of k.

Solution,

The given polynomial is

f(x) = x³-3kx²+4x-5

The sum of roots of the equation = 6

Also, the sum of roots = -b/a

where bis the coefficient of x² and a is the coefficient of x³.

So,

-(-3k)/2 = 6

k/2 = 2

k = 4

Hence, the value of k is 4.

Answer 2

Given; the sum of zeroes of the polynomial f(x) 2x³-3kx²+4x-5 is 6,

To Find; the Value of k

Solution; Sum of zeroes=-b/a

So on comparing equation b=-3k and a =2

6=3k/2

k=4

Hence the value of k is 4