Math, asked by HariNarmadha, 1 year ago

if the sum of zeroes of the polynomial p(x)=(a+1)x^+(2a+3)x+(3a+4) is -1 find the product of the zeroes

Answers

Answered by QUEEN007
12
Hey Friend ☺

p ( x ) = ( a + 1 )x^2 + ( 2a + 3 )x + ( 3a + 4 )

The sum of zeroes is - 1

i. e.

2a + 3 = - 1

》2a = - 1 - 3

》2a = - 4

》a = - 2

Product of zeroes = ( 3a + 4 )

= 3 ( - 2 ) + 4

= - 6 + 4

= - 2

So the product of zeroes is - 2

Hope it helps you ..!


HariNarmadha: then what about (a+1)x^2.
QUEEN007: do not consider it
HariNarmadha: sry sis i can't understand
HariNarmadha: why we should not consider it
Answered by Anonymous
5
(a+1)x sq + (2a+3)x +(3a+4)=0

Here a= (a+1) b= (2a+3) c= (3a+4)
Sum of zeros = -1
-b/a=-1

-(2a+3)/a+1=-1

-2a-3=-a-1

a= -2 eq 1)

Now product of roots = c/a
(3a+4)/a+1

Now from eqn 1) putting value of a
3(-2)+4/(-2)+1

-6+4/-2+1

-2/-1

= 2 Ans

HariNarmadha: , super
Anonymous: Thnx
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