if the sum of zeroes of the polynomial p(x)=(a+1)x^+(2a+3)x+(3a+4) is -1 find the product of the zeroes
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Answered by
12
Hey Friend ☺
p ( x ) = ( a + 1 )x^2 + ( 2a + 3 )x + ( 3a + 4 )
The sum of zeroes is - 1
i. e.
2a + 3 = - 1
》2a = - 1 - 3
》2a = - 4
》a = - 2
Product of zeroes = ( 3a + 4 )
= 3 ( - 2 ) + 4
= - 6 + 4
= - 2
So the product of zeroes is - 2
Hope it helps you ..!
✌
p ( x ) = ( a + 1 )x^2 + ( 2a + 3 )x + ( 3a + 4 )
The sum of zeroes is - 1
i. e.
2a + 3 = - 1
》2a = - 1 - 3
》2a = - 4
》a = - 2
Product of zeroes = ( 3a + 4 )
= 3 ( - 2 ) + 4
= - 6 + 4
= - 2
So the product of zeroes is - 2
Hope it helps you ..!
✌
HariNarmadha:
then what about (a+1)x^2.
Answered by
5
(a+1)x sq + (2a+3)x +(3a+4)=0
Here a= (a+1) b= (2a+3) c= (3a+4)
Sum of zeros = -1
-b/a=-1
-(2a+3)/a+1=-1
-2a-3=-a-1
a= -2 eq 1)
Now product of roots = c/a
(3a+4)/a+1
Now from eqn 1) putting value of a
3(-2)+4/(-2)+1
-6+4/-2+1
-2/-1
= 2 Ans
Here a= (a+1) b= (2a+3) c= (3a+4)
Sum of zeros = -1
-b/a=-1
-(2a+3)/a+1=-1
-2a-3=-a-1
a= -2 eq 1)
Now product of roots = c/a
(3a+4)/a+1
Now from eqn 1) putting value of a
3(-2)+4/(-2)+1
-6+4/-2+1
-2/-1
= 2 Ans
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