Question

if the sum of zeroes of the polynomial p(x) = (k2 -14 ) x2-2x-4 is 1,then find the value of k.

Answer 1

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Answer 2

Answer:

k=±4

Step-by-step explanation:

The given polynomial is:

p(x)=$(k^{2}-14)x^{2}-2x-4=1$

Comparing with the general Quadratic equation $ax^{2}+bx+c=0$, we get the sum of zeroes of the polynomial=$-\frac{b}{a}$

Therefore, $-\frac{b}{a}=1$ (Given)

$\frac{2}{k^{2}-14}=1$

$2=k^{2}-14$

$k^{2}=16$

$k={\pm}4$