Math, asked by rh6440625, 3 months ago

If the sum of zeroes of the quadratic polynomial 3x2 - kx + 6 is 3, then find
the value of k.​

Answers

Answered by Anonymous
23

Answer:

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Answered by pulakmath007
3

SOLUTION

GIVEN

The sum of zeroes of the quadratic polynomial 3x² - kx + 6 is 3

TO DETERMINE

The value of k

FORMULA TO BE IMPLEMENTED

If  \alpha \:  \: and \:  \:  \beta \: are the zeroes of the quadratic polynomial a {x}^{2}  + bx + c

Then

 \displaystyle \:  \alpha  +   \beta \:  =  -  \frac{b}{a}  \:  \: and \:  \:   \: \alpha \beta \:  =  \frac{c}{a}

EVALUATION

Here the given Quadratic polynomial is

3x² - kx + 6

Comparing with ax² + bx + c we get

a = 3 , b = - k , c = 6

So the sum of the zeroes

 =  \displaystyle \sf{  - \frac{ - k}{3} }

 =  \displaystyle \sf{  \frac{k}{3} }

So by the given condition

  \displaystyle \sf{  \frac{k}{3}  = 3}

  \displaystyle \sf{  \implies k = 9}

FINAL ANSWER

The required value of k = 9

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