If the sum of zeroes of the quadratic polynomial 3x2 – kx + 6 is 3, then find the value of k.
Answers
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EXPLANATION.
Quadratic equation.
⇒ 3x² - kx + 6 = 0 is 3.
As we know that,
Put the value of x = 3 in equation, we get.
⇒ 3(3)² - k(3) + 6 = 0.
⇒ 3(9) - 3k + 6 = 0.
⇒ 27 + 6 - 3k = 0.
⇒ 33 - 3k = 0.
⇒ 3k = 33.
⇒ k = 11.
MORE INFORMATION.
Nature of the factors of the quadratic expression.
(1) = Real and different, if b² - 4ac > 0.
(2) = Rational and different, if b² - 4ac is a perfect square.
(3) = Real and equal, if b² - 4ac = 0.
(4) = If D < 0 Roots are imaginary and unequal or complex conjugate.
Answered by
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Question:
- If the sum of zeroes of the quadratic polynomial 3x2 – kx + 6 is 3, then find the value of k.
Solution:
Need to find: Find the value of k ?
Step-by-step explanation:
As we know that,
- ax² + by + c = 0 ➠ -b/a = sum of zeros
➠ 3x² - kx + 6 = 3
❍Let us consider that,
a = 3 ,b = -k and c = 6 ,we get:
➠ -(-k)/3 = 3
➠ k = 3 × 3
➠ k = 9
- Therefore,The value of k is 9.
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