Question

If the sum of zeros of a polynomial x^2-(k+3)x +(5k-3) is one fourth of product of zeros . Find the value of k?

Answer 1

Answer:

Step-by-step explanation:

A=1 , b=-(k+3) , c=5k-3

Product of zeroes = c/a

=5k-3/1 = 5k-3

Alpha + beta = -b/a

-(-k+3) / 1 = k+3

Atq

K+3 = 5k-3 / 4

4(k+3) = 5k-3

4k+12=5k-3

5k-4k = 12+3

K=15

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