if the sum of zeros of quadratic polynomial 3 x ki power 2 minus kx + 6 is 3
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Answer:
k=9
Step-by-step explanation:
3x²-kx+6=0
α and β are zeroes of the above polynomial
then,
α+β=3 (given)
α+β=-b/a
b=-k
a=3
so,
-(-k)/3 = 3
k/3=3
k=9
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