If the sum of zeros of quadratic polynomial p(x) = px² - 4x + 2k is same as their product Find k
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Step-by-step explanation:
Given :-
The sum of zeros of quadratic polynomial p(x) = px² - 4x + 2k is same as their product .
To find :-
Find the value of k ?
Solution :-
Given Quadratic Polynomial is p(x) = px² - 4x + 2k
On comparing this with the standard quadratic Polynomial ax²+bx+c
We have
a = p
b = -4
c = 2k
We know that
Sum of the zeroes = -b/a
=> -(-4)/p
=> 4/p
Sum of the zeores = 4/p ----------(1)
Product of the zeroes = c/a
=> 2k/p
Product of the zeroes = 2k/p ------(2)
Given that
The sum of zeros of quadratic polynomial p(x) = px² - 4x + 2k is same as their pproduct
=> (1) = (2)
=> 4/p = 2k/p
On applying cross multiplication then
=> 2k×p = 4×p
=> 2k = 4×p/p
=> 2k = 4
=> k = 4/2
=> k = 2
Therefore, k = 2
Answer:-
The value of k for the given problem is 2
Used formulae:-
- The standard quadratic Polynomial is ax²+bx+c
- Sum of the zeroes = -b/a
- Product of the zeroes = c/a
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