Math, asked by Mansii8549, 10 months ago

if the sum of zeros of the polynomial 5x^2-(3+k)x+7 is zero, then find the zeros of the polynomial 2x^2-(29k+11)x+30

Answers

Answered by shallu22
0

Step-by-step explanation:

Let p & q be the zeroes of above polynomial and sum of zeroes is(-

p+q= - b/a

P+q= - (-(3+k))/5

=3+k/5

Nw will equate it by zeroes of polynomial second.

3+k/5 = - (-(29k+11))/2

(3+k/5) = 29k+11)/2

2(3+k) = 5(29k+11)

6+2k = 145k+55

2k-145k = 55-6

-143k = 49

K = 49/-143

Answered by brunoconti
0

Answer:

Step-by-step explanation:

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