if the sum of zeros of the polynomial 5x^2-(3+k)x+7 is zero, then find the zeros of the polynomial 2x^2-(29k+11)x+30
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Step-by-step explanation:
Let p & q be the zeroes of above polynomial and sum of zeroes is(-
p+q= - b/a
P+q= - (-(3+k))/5
=3+k/5
Nw will equate it by zeroes of polynomial second.
3+k/5 = - (-(29k+11))/2
(3+k/5) = 29k+11)/2
2(3+k) = 5(29k+11)
6+2k = 145k+55
2k-145k = 55-6
-143k = 49
K = 49/-143
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