Math, asked by saad217, 2 days ago

if the sum oo zeroes of polynomial p(x) =(k²-14)-x²-2x-12 is 1 then find the value of k​

Answers

Answered by simpipandey544
1

Answer:

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Step-by-step explanation:

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Answered by kinzal
3

We know that,

The sum of Zeros (Products) = α + ß = -b/a

And it's given in question = 1

Now, We can write it like below ,

→ α + ß = -b/a

→ 1 = -b/a

In polynomial equation

a = (k² - 14)

b = - 2

c = - 12

Now, only we have to put these values in The sum of Zeros

Hence, In

→ 1 = - b/a

→ 1 = -(-2)/(k² - 14)

→ k² - 14 = 2

→ k² = 2 + 14

→ k² = 16

→ k = √16

Square root of 16 is 4

Hence,

k = 4

I hope it helps you...

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