if the sum oo zeroes of polynomial p(x) =(k²-14)-x²-2x-12 is 1 then find the value of k
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We know that,
The sum of Zeros (Products) = α + ß = -b/a
And it's given in question = 1
Now, We can write it like below ,
→ α + ß = -b/a
→ 1 = -b/a
In polynomial equation
a = (k² - 14)
b = - 2
c = - 12
Now, only we have to put these values in The sum of Zeros
Hence, In
→ 1 = - b/a
→ 1 = -(-2)/(k² - 14)
→ k² - 14 = 2
→ k² = 2 + 14
→ k² = 16
→ k = √16
Square root of 16 is 4
Hence,
→ k = 4
I hope it helps you...
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