Question

If the sum squares of 3 consecutive even number is 116. Find those numbers

Answer 1

Answer:

x+x+1+x+2=116

3x+3=116

3x=113

x=113/3

x=37⅔

Answer 2

Answer:

4 , 6 , 8

-8, -6 , -4

Step-by-step explanation:

let the numbers be

x , x+2 , x +4

According to question ,${x}^{2} + {(x + 2)}^{2} + {(x + 4)}^{2} = 116 \\ {x}^{2} + {x}^{2} + 4x + 4 + {x}^{2} + 8x + 16 = 116 \\ 3 {x}^{2} + 12x + 20 - 116 = 0 \\ 3 {x}^{2} + 12x \: - 96 = 0 \\ 3( {x }^{2} + 4x - 32) = 0 \\ {x}^{2} + 4x - 32 = 0 \\ {x}^{2} + 8x - 4x - 32 = 0 \\ x(x + 8) - 4(x + 8) = 0 \\ (x - 4)(x + 8) = 0 \\ x - 4 = 0 \: \: \: \: \: x = 4 \\ x + 8 = 0 \: \: \: \: x = - 8$