Question

if the sum to n terms of ab A. P is [4n^2 - 3n]
[--------------] then the nth term of
[ 4 ]
the A. P is??

Please answer this 2 morrow I have an exam please.....!!

Answer 1

HEYA DEAR!!!!!!!


HERE IS THE ANSWER TO YOUR QUESTION..........


sn=4n^2-3n

s1=4*1-3*1=1

s2=4*2^2-3*2=16-6=10

s3=4*3^2-3*3=36-9=27

a1=s1=1

a2=s2-s1=10-1=9

a3=s3-s2=27-10=17

first term=a=a1=1

common difference=d=a2-a1=9-1=8

n th term=an= a+(n-1)d=1+(n-1)8=1+8n-8=8n-7


HOPE IT HELPS.......
PLEASE MARK AS BRAINLIEST.......

Answer 2

the above answer is correct