if the supleemntal of angle is 3tim it's complement find angles
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let x be that angle, y its supplement and z its complement.
y= 180 - x and z= 90 - x
the supplement of x is three times its complement, so y=3z
180 - x = 3( 90 - x)
180 - x = 270 - 3x
- x + 3x= 270 -180
2x= 90
x=45.
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y= 180 - x and z= 90 - x
the supplement of x is three times its complement, so y=3z
180 - x = 3( 90 - x)
180 - x = 270 - 3x
- x + 3x= 270 -180
2x= 90
x=45.
Plse Mark me as brainlist
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