Question

If the supplement of an angle is 1/5 of itself find the supplement and the angles

Answer 1

$\huge\mathbb{\underline{SOLUTION:-}}$

• The sum of angles of the supplementary angles is 180°

$\boxed{\sf{Supplement\:angle=180{}^{\circ}}}$

$\bf\underline{\underline{According\:to\: Question:-}}$

• let the angle be x

• It's supplement is 180°-x

• It is given that the

• $\sf\implies \frac{1}{5}\:of\:it's\: supplement$

Now let's find the Angle:-

$\sf\implies x=\frac{1}{5}\times (180{}^{\circ}-x)\\ \\ \sf\implies 5x=180{}^{\circ}-x\\ \\ \sf\implies 5x-x=180{}^{\circ}\\ \\ \sf\implies 4x=180{}^{\circ}\\ \\ \sf\implies x=\cancel{\frac{180{}^{\circ}}{4}}=45{}^{\circ}\\ \\ \sf\implies x=45{}^{\circ}$

• The value of x which is angle is 45°

• To find The supplement angle

$\sf\implies 180{}^{\circ}-x\\ \\\sf\implies 180{}^{\circ}-45{}^{\circ}\\ \\ \sf\implies 135{}^{\circ}$

$\boxed{\sf{\purple{Angle=45{}^{\circ}\:\:\:\:Supplement=135{}^{\circ}}}}$

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Answer 2

Answer:

30,150

Step-by-step explanation:

there is a minor mistake in the above answer

its not 180/4

its 180/6=30

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